将字符串形式的 JSON 数据格式化为缩进形式。通常使用 json_encode 转换出来的 JSON 串没有缩进。
有了本文分享的这个方法,就不用再担心这个问题了。
本代码:
默认使用了 tab 缩进,如果要改成空格,替换变量 $indentStr 即可。
代码:
<?php /** * Indents a flat JSON string to make it more human-readable. * @param string $json The original JSON string to process. * @return string Indented version of the original JSON string. * @site www.jb200.com */ function indent ($json) { $result = ''; $pos = 0; $strLen = strlen($json); $indentStr = ' '; $newLine = "n"; $prevChar = ''; $outOfQuotes = true; for ($i=0; $i<=$strLen; $i++) { // Grab the next character in the string. $char = substr($json, $i, 1); // Are we inside a quoted string? if ($char == '"' && $prevChar != '') { $outOfQuotes = !$outOfQuotes; // If this character is the end of an element, // output a new line and indent the next line. } else if(($char == '}' || $char == ']') && $outOfQuotes) { $result .= $newLine; $pos --; for ($j=0; $j<$pos; $j++) { $result .= $indentStr; } } // Add the character to the result string. $result .= $char; // If the last character was the beginning of an element, // output a new line and indent the next line. if (($char == ',' || $char == '{' || $char == '[') && $outOfQuotes) { $result .= $newLine; if ($char == '{' || $char == '[') { $pos ++; } for ($j = 0; $j < $pos; $j++) { $result .= $indentStr; } } $prevChar = $char; } return $result; } ?>