微博开发之@替换示例代码

$users['pony']      = '马化腾';
$users['ponyma']    = '坡泥马';
$users['ponyli']    = '坡泥李';
$text = "@pony:特别声明,@ponyli@ponyma@ponywong@ponylao什么的都不是我";
preg_match_all('/@w+/', $text, $matches);
if(is_array($matches[0]) && !empty($matches[0])){
    $replaces       = array_combine($matches[0], $matches[0]);
}
foreach($users as $userid=>$username){
    $replaces['@'.$userid]  = "<a href='http://t.qq.com/{$userid}'>{$username}</a>";
}
$html               = strtr($text, $replaces);
echo $html;