#filter out some unwanted tags
def passed(item):
try:
return item != "techbrood" #can be more a complicated condition here
except ValueError:
return False
org_words = [["this","is"],["demo","from"],["techbrood"]]
words = [filter(passed, item) for item in org_words]
注意:python2.x和Python3.x对于filter/map的处理并不兼容,在Python2.x里面直接返回一个list.
在Python3.x里返回一个iterable对象,比如<filter object at 0x000000000251C978>,后面那串数字是对象引用地址。
可以使用list(words)转换。