linux下统计目录中文件的大小，代码如下：
#!/bin/sh
# filename: df_dir.sh
#edit www.jb200.com
usage(){
echo -e "nUsage: `basename $0` DIRECTORY [MIN_SIZE]n"
echo "Get file list of DIRECTORY, then output them in order by size."
echo "If MIN-SIZE is specified, only print those greater than MIN-SIZE.";
echo -e "MIN-SIZE is non-zero integer optionally followed by a k/K/m/M/g/G.n";
exit
}
if [ $# -lt 1 ] || [ $# -gt 2 ]; then
usage
elif [ ! -d $1 ] ; then
echo -e "nERROR: $1 is not a directory or does not existn"
exit
fi
## delete the slash at the end of directory name
## eg: /usr/share/ --> /usr/share
dir=${1%/}
## if MIN_SIZE is specified
if [ -n $2 ] ; then
## get the last char of MIN_SIZE
unit=${2: -1}
## get thE NUMBER part of MIN_SIZE except the unit
size=${2%?}
## if size is not an integer number, then exit
echo $size|awk '{if($0~/[^0-9]/) exit 1}'
[ $? -ne 0 ] && usage
case $unit in
g|G) msize=$[size * 1024 * 1024]
;;
m|M) msize=$[size * 1024]
;;
k|K) msize=$size
;;
[0-9]) msize=$2
;;
*) usage
;;
esac
else
msize=0
fi
du -s $dir/*|sort -rn|awk -v size=$msize '{
if($1>1024*1024 && $1>size) printf "%5.1fGt%sn",$1/1024/1024,$2;
else if($1>1024 && $1>size) printf "%5.1fMt%sn",$1/1024,$2;
else if($1>size) printf "%5dKt%sn",$1,$2}'
用法: dfdir <目录> [最小文件大小,可省略,单位可为k/K/m/M/g/G, 默认为K]
说明: 大小超过1G的文件输出单位为G,超过1M的文件输出为单位为M
例1:
例2:
例3:
个人感觉，这个shell脚本写的不错，主要是多参数的灵活应用，方便输出想要的数据格式。
有需要统计目录文件大小的朋友，建议参考下这个，肯定有帮助哦。