sql统计查询实例代码

发布时间:2020-08-27编辑:脚本学堂
收集一些用sql脚本进行统计的代码,13个问题与相应解答,都是比较常用的,千万别错过哦。

首先,创建用到的数据表。
 

复制代码 代码示例:
CREATE TABLE `stuscore` (  
  `id` int(11) NOT NULL auto_increment,  
  `name` varchar(20) default NULL,  
  `subject` varchar(20) default NULL,  
  `score` varchar(20) default NULL,  
  `stuid` varchar(10) default NULL,  
  PRIMARY KEY  (`id`)  
) ENGINE=innodb DEFAULT CHARSET=utf8;  
 

 
然后,添加测试数据。
 

复制代码 代码示例:
/*Data for the table `stuscore` */
insert  into `stuscore`(`id`,`name`,`subject`,`score`,`stuid`) values
(1,'张三','数学','89','1'),  
(2,'张三','语文','80','1'),  
(3,'张三','英语','70','1'),  
(4,'李四','数学','90','2'),  
(5,'李四','语文','70','2'),  
(6,'李四','英语','80','2'); 

#--问题及解答:

1. 计算每个人的总成绩并排名(要求显示字段:姓名,总成绩)
 

复制代码 代码示例:
select name,sum(score) as allscore from stuscore group by name order by allscore desc 

2. 计算每个人的总成绩并排名(要求显示字段: 学号,姓名,总成绩)
 

复制代码 代码示例:
select stuid,name,sum(score) as allscore from stuscore group by name order by allscore desc 

3. 计算每个人单科的最高成绩(要求显示字段: 学号,姓名,课程,最高成绩)
 

复制代码 代码示例:
SELECT t1.stuid,t1.name,t1.subject,t1.score from stuscore t1,  
(SELECT stuid,max(score) as maxscore from stuscore group by stuid) t2
where t1.stuid=t2.stuid and t1.score=t2.maxscore 

4. 计算每个人的平均成绩(要求显示字段: 学号,姓名,平均成绩)
 

复制代码 代码示例:
select distinct t1.stuid,t1.name,t2.avgscore from stuscore t1,  
(select stuid,avg(score) as avgscore from stuscore group by stuid) t2
where t1.stuid=t2.stuid 

5. 列出各门课程成绩最好的学生(要求显示字段: 学号,姓名,科目,成绩)
 

复制代码 代码示例:
select  t1.stuid,t1.name,t1.subject,t2.maxscore from stuscore t1,  
(select subject,max(score) as maxscore from stuscore group by subject) t2
where t1.subject=t2.subject and t1.score=t2.maxscore 

6. 列出各门课程成绩最好的两位学生(要求显示字段: 学号,姓名,科目,成绩)
 

复制代码 代码示例:
select distinct t1.* from stuscore t1 where t1.stuid in
(select top 2 stuscore.stuid from stuscore where subject = t1.subject order by score desc)
order by t1.subject 
 

该语句未测试,目前知道在mysql下无法运行。mysql不支持select top。

7.
 

复制代码 代码示例:
select stuid as 学号,name as 姓名,  
sum(case when subject='语文' then score else 0 end) as 语文,  
sum(case when subject='数学' then score else 0 end) as 数学,  
sum(case when subject='英语' then score else 0 end) as 英语,  
sum(score) as 总分,(sum(score)/count(*)) as 平均分  
from stuscore  
group by stuid,name
order by 总分 desc 

8. 列出各门课程的平均成绩(要求显示字段:课程,平均成绩)
select subject,avg(score) as avgscore from stuscore group by subject 

9. 列出数学成绩的排名(要求显示字段:学号,姓名,成绩,排名)
 

复制代码 代码示例:
select * from stuscore where subject ='数学' order by score desc  

 
不知道我自己想法对不对?

10. 列出数学成绩在2-3名的学生(要求显示字段:学号,姓名,科目,成绩)
 

复制代码 代码示例:
select t3.*  from(  
select top 2 t2.*  from (  
select top 3 name,subject,score,stuid from stuscore where subject='数学' 
order by score desc 
) t2 order by t2.score  
) t3 order by t3.score desc 

11. 求出李四的数学成绩的排名
 

复制代码 代码示例:
declare @tmp table(pm int,name varchar(50),score int,stuid int)  
insert into @tmp select null,name,score,stuid from stuscore where subject='数学' order by score desc 
declare @id int 
set @id=0;  
update @tmp set @id=@id+1,pm=@id  
select * from @tmp where name='李四' 

12.
 

复制代码 代码示例:
select subject,
(select count(*) from stuscore where score<60 and subject=t1.subject) as 不及格,  
(select count(*) from stuscore where score between 60 and 80 and subject=t1.subject) as 良,  
(select count(*) from stuscore where score >80 and subject=t1.subject) as 优  
from stuscore t1 group by subject 

13.统计如下:数学:张三(50分),李四(90分),王五(90分),赵六(76分)
 

复制代码 代码示例:
declare @s varchar(1000)  
set @s='' 
select @s =@s+','+name+'('+convert(varchar(10),score)+'分)' from stuscore where subject='数学'
set @s=stuff(@s,1,1,'')  
print '数学:'+@s

说:第10,11,13题未验证,大家在使用时,注意测试。